两道数学题,求过程
2014-08-17
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18.x²-y²=2xy
(x²-y²)²=(2xy)²
x^4-2x²y²+y^4=4x²y²
x^4+2x²y²+y^4=8x²y²
(x²+y²)²=8x²y²
x²+y²=±2√2xy
(x-y)/(x+y)=(x²-y²)/(x+y)²=2xy/(x²+y²+2xy)=2xy/(±2√2xy+2xy)
=1/(1±√2)
=±√2-1
19.=a/b+a/c+b/c+b/a+c/a+c/b
=a+c/b +a+b/c+ b+c/a
=-b/b + -c/c + -a/a
=-2
(x²-y²)²=(2xy)²
x^4-2x²y²+y^4=4x²y²
x^4+2x²y²+y^4=8x²y²
(x²+y²)²=8x²y²
x²+y²=±2√2xy
(x-y)/(x+y)=(x²-y²)/(x+y)²=2xy/(x²+y²+2xy)=2xy/(±2√2xy+2xy)
=1/(1±√2)
=±√2-1
19.=a/b+a/c+b/c+b/a+c/a+c/b
=a+c/b +a+b/c+ b+c/a
=-b/b + -c/c + -a/a
=-2
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是负三吧
追答
-3写错了,抱歉
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