Question

请问这题怎么做啊 分解因式

求助！

Answer 1

(1-2a-a^2)b+a(a-1)(2b^2-1)
=2a(a-1)b^2+(1-2a-a^2)b-a(a-1)
=(2ab+a-1)[a-1)b-a]

追问

还有两道呢

追答

①x^3+(2a+1)x^2+(a^2+2a-1)x+(a^2-1)
x=-1代入原式=0.所以(x+1)是原式的因式
∴原式=(x^3-x)+(2ax^2+2ax)+(x^2-1)+(a^2x+a^2)
=(x+1)(x^2-x+2ax+x-1+a^2)
=(x+1)(x^2+2ax+a^2)
=(x+1)(x+a)^2
②y(y+1)(x^2+1)+x(2y^2+2y+1)
=y(y+1)x^2+(2y^2+2y+1)x+y(y+1)
=(yx+y+1)[(y+1)x+y]