Question

C语言 socket编程 客户端只send一次 但是服务器会循环执行这条命令 在线等

代码如下：
server端：
int main(int agrc, char *argv[])
{
//一些定义性的东西

while(1) //waiting for client
{
comm_socket= accept(ser_socket, (struct sockaddr *)&cliaddr, &addrlen); /*start accept mode, waiting until a specific socket to respone*/

recv(comm_socket, recv_buff,sizeof(recv_buff), 0); /*detectsomeone is comming*/
printf("%s\n",recv_buff); //recevingentering-command

strcpy(welcome_buff,"Welcometo my server!\n"); /*sendingwelcome message*/
send(comm_socket,welcome_buff, sizeof(welcome_buff)+1, 0); // sending welcome message

while(1)
{
recv(comm_socket,recv_buff, sizeof(recv_buff), 0); /*receiveclient's command*/
printf("%s\n",recv_buff); //receving client command

send(comm_socket,send_buff, strlen(send_buff)+1, 0);
……有省略（没什么重要的）
}
}
}
个人觉得问题还是出在server端吧，client就不放了，client就是中规中矩的那种。
想实现client端等待user输入一个东西，然后send给server端，然后server端send一个回复给client端，然后client端可以再次输入，再次执行send和recv。
可是现在的问题是如果我在client端输入一个1，server端识别了这个1之后执行相应的命令然后send 2给客户端，然后server端不会再次等待client端user的输入，而是不断将1作为recv，不断send 2给客户端，求大神解答！

Answer 1

recv(comm_socket,recv_buff, sizeof(recv_buff), 0); /*receiveclient's command*/

改成
int ret = recv(comm_socket,recv_buff, sizeof(recv_buff), 0); /*receiveclient's command*/

if ret == -1 || ret == 0
break

== -1 表示出错， =0 表示 socket 已经关闭。