Question

怎么做啊求解

Answer 1

追答

望采纳

Answer 2

(1)原式=(a²-b²)(a²+b²)(a^4+b^4)(a^8+b^8)

=(a^4-b^4)(a^4+b^4)(a^8+b^8)
=(a^8-b^8)(a^8+b^8)=(a^16-b^16)
(2)原式=(10000+1)(10000-1)=10000²-1=99999999
(3)原式=(3m-1/2)[-(3m+1/2)][-(9m²+1/4)]
=(3m-1/2)(3m+1/2)(9m²+1/4)
=(9m²-1/4)(9m²+1/4)=81m^4-1/16
(4)原式=105²-(105+1)(105-1)=105²-(105²-1)=1

Answer 3

1) =a^16-b^16 平方差公式
2) =（10000+1）（10000-1）=100000000-1=99999999
3) = -(9m^2-1/4 )* -(9m^2+1/4)=81m^4-1/16
4) = 105^2-(105+1)(105-1)=105^2-105^2+1=1

Answer 4

解：
原式=（a^2-b^2）（a^2+b^2）（a^4+b^4）（a^8-b^8）
=(a^4-b^4)(a^4+b^4)(a^8-b^8)
=(a^8-b^8)(a^8+b^8)
=a^16-b^16
原式=(3m-1/2)(3m+1/2)(9m^2+1/4)
=(9m^2-1/4)(9m^2+1/4)
=(81m^4-1/16)
原式=105^2-(105+1)(105-1)
=105^2-105^2+1
=1