定积分求帮助
3个回答
展开全部
(1)令x=tant,则dx=sec^2tdt
原式=∫(π/4,π/3) sec^2t/(tan^2t*sect)dt
=∫(π/4,π/3) cost/sin^2tdt
=∫(π/4,π/3) d(sint)/sin^2t
=-1/sint|(π/4,π/3)
=-2/√3+√2
=√2-(2/3)*√3
(2)令x=asint,则dx=acostdt
原式=∫(0,π/2) a^2*sin^2t*acost*acostdt
=a^4*∫(0,π/2) sin^2t*cos^2tdt
=(a^4/4)*∫(0,π/2) sin^2(2t)dt
=(a^4/8)*∫(0,π/2) (1-cos4t)dt
=(a^4/8)*[t-(1/4)*sin4t]|(0,π/2)
=(a^4/8)*(π/2)
=a^4*(π/16)
原式=∫(π/4,π/3) sec^2t/(tan^2t*sect)dt
=∫(π/4,π/3) cost/sin^2tdt
=∫(π/4,π/3) d(sint)/sin^2t
=-1/sint|(π/4,π/3)
=-2/√3+√2
=√2-(2/3)*√3
(2)令x=asint,则dx=acostdt
原式=∫(0,π/2) a^2*sin^2t*acost*acostdt
=a^4*∫(0,π/2) sin^2t*cos^2tdt
=(a^4/4)*∫(0,π/2) sin^2(2t)dt
=(a^4/8)*∫(0,π/2) (1-cos4t)dt
=(a^4/8)*[t-(1/4)*sin4t]|(0,π/2)
=(a^4/8)*(π/2)
=a^4*(π/16)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询