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f(x)=(x-4)(x+1)^(2/3)
f'(x)=(x+1)^(2/3)+(x-4)(2/3)(x+1)^(-1/3)
=(x+1)^(2/3)+(x-4)(2/3)(x+1)^(-1/3)
=[x+1+(2/3)(x-4)](x+1)^(-1/3)
=5(x-1)/(3(x+1)^(-1/3))
f'(x)=(x+1)^(2/3)+(x-4)(2/3)(x+1)^(-1/3)
=(x+1)^(2/3)+(x-4)(2/3)(x+1)^(-1/3)
=[x+1+(2/3)(x-4)](x+1)^(-1/3)
=5(x-1)/(3(x+1)^(-1/3))
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