经济数学题，
1个回答
展开全部
(1)
lim(x->3) (x^2-2x-3)/(x^2-9)
=lim(x->3) (x-3)(x+1)/[(x-3)(x+3)]
=lim(x->3) (x+1)/(x+3)
=4/6
=2/3
(2)
lim(x->0)sin3x/sin2x
=lim(x->0)3x/(2x)
=3/2
(3)
lim(x->0) (1-cosx)/x^2
=lim(x->0) (1/2)x^2/x^2
=1/2
lim(x->3) (x^2-2x-3)/(x^2-9)
=lim(x->3) (x-3)(x+1)/[(x-3)(x+3)]
=lim(x->3) (x+1)/(x+3)
=4/6
=2/3
(2)
lim(x->0)sin3x/sin2x
=lim(x->0)3x/(2x)
=3/2
(3)
lim(x->0) (1-cosx)/x^2
=lim(x->0) (1/2)x^2/x^2
=1/2
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
