Question

求不定积分 ∫(x²+3)/(x²-1)dx

求不定积分∫(3/x²-1)dx

Answer 1

朋友，你好！学习过程如图rt，希望能帮到你解决问题

Answer 2

(x²+3）/(x²-1)=1+[4/(x²-1)]=1+2[1/(x-1)-1/(x+1)]。∴原式=x+2ln丨(x-1)/(x+1)丨+C。