Question

linux 操作系统中shell过滤

当前目录有一文本，文本中有0~28若干组整数数值以逗号为间隔

有可能是，
0,2,12,24或者其它数值组合，也有可能，0到28数值全部都存在，数值间以逗号为间隔
如何实现以下功能，
当文本中的数值有0时执行一条指定的指令
有1时，也执行一条不同指令，
以此类推，存在的每个数值执行一条特定的指令

如何判断文本中存在的数值，并执行对应的指令呢？如
当文本中有
1,3,8.11,13,21,28
执行各数值对应的指令！
shell该如何写？

Answer 1

这不简单，for循环嵌套case多分枝选择结构，一楼的回答我就不说什么了，根本就没有/bash/这个路径，sh自然也不会存在在这个路径上。这个脚本就是可能的数值太多，case分支写得累……。算了，我给你写个吧。

说明：此脚本接收脚本后跟的第一个参数为读取定义数值的文本，比如说你在工作路径上有个叫test的文件，该文件定义了需要包含的数字，脚本本身的文件名是num那么执行该脚本的命令是./num ./test

每个数字对应的命令自己改吧，我这里全是打印文件里包含了对应的数值到标准输出上。以下脚本在ubuntu server 8.04测试通过。

#! /bin/bash
for var in `sed 's/,/ /g' $1` #注意，包围sed语句的是反引号，即字母键盘上方数字1左边的那个键
do
case $var in
0)
echo "0 is in the string\.";;
1)
echo "1 is in the string\.";;
2)
echo "2 is in the string\.";;
3)
echo "3 is in the string\.";;
4)
echo "4 is in the string\.";;
5)
echo "5 is in the string\.";;
6)
echo "6 is in the string\.";;
7)
echo "7 is in the string\.";;
8)
echo "8 is in the string\.";;
9)
echo "9 is in the string\.";;
10)
echo "10 is in the string\.";;
11)
echo "11 is in the string\.";;
12)
echo "12 is in the string\.";;
13)
echo "13 is in the string\.";;
14)
echo "14 is in the string\.";;
15)
echo "15 is in the string\.";;
16)
echo "16 is in the string\.";;
17)
echo "17 is in the string\.";;
18)
echo "18 is in the string\.";;
19)
echo "19 is in the string\.";;
20)
echo "20 is in the string\.";;
21)
echo "21 is in the string\.";;
22)
echo "22 is in the string\.";;
23)
echo "23 is in the string\.";;
24)
echo "24 is in the string\.";;
25)
echo "25 is in the string\.";;
26)
echo "26 is in the string\.";;
27)
echo "27 is in the string\.";;
28)
echo "28 is in the string\.";;
*)
echo "One or more variable\(s\) in $1 is out of range!";;
esac
done

Answer 2

#! /bash/sh
FILE=/../../..
[ $grep "^0," $FILE ] || [ $grep ",0," $FILE ] || [ $grep ",0$" $FILE ] && comand
[ $grep "^1," $FILE ] || [ $grep ",1," $FILE ] || [ $grep ",1$" $FILE ] && comand
[ $grep "^2," $FILE ] || [ $grep ",2," $FILE ] || [ $grep ",2$" $FILE ] && comand
....