Question

c语言编程求1+3+5+……+（2n-1）

Answer 1

#include<stdio.h>const int n=5;//定义n的大小int main(){ static int sum=0; for(int i=1;i<=n;i++) { sum=sum+2*i-1; } printf("sum=%d\n",sum); return 0;}

Answer 2

#include<stdio.h>
main()
{
int i,n,sum=0;
printf("please input n:");
scanf("%d",&n);
for(i=1;i<=n;i++)
sum=sum+(i*2-1)
printf("sum=%d",sum);
}

Answer 3

#include<stdio.h>
main()
{
int i=1,n,sum=0;
printf("please input n:");
scanf("%d",&n);
while(i<=n;)
sum=sum+(i*2-1)
printf("sum=%d",sum); i++;}
}