Question

求学霸！！！助攻！！！急！！！过程？！！！！

Answer 1

由已知条件可以得出x<0，且y<0;
x+y=-4
两边平方：
x²+y²+2xy=16
x²+y²+2*6=16
x²+y²=16-12=4;
(1)
原式=√[(xy)/x²]+√[(xy)/y²]
=√(xy)/(-x)+√(xy)/(-y)
=-y√(xy)/(xy)-x√(xy)/(xy)
=-(x+y)√(xy)/(xy)
=-(-4)√(6)/6
=(2/3)√6;
(2)
原式=x√[x²/(xy)]+y√[y²/(xy)]
=x(-x)/√(xy)+y(-y)/√(xy)
=-x²/√(xy)-y²/√(xy)
=-(x²+y²)/√(xy)
=-(4)/√(6)
=-4√6/(√6*√6)
=-4√6/6
=-(2/3)√6;