
计算(3-1)(32+1)(34+1)(38+1)(316+1)=______
1个回答
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原式=
(3+1)(3-1)(32+1)(34+1)(38+1)(316+1)
=
(32-1)(32+1)(34+1)(38+1)(316+1)
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(34-1)(34+1)(38+1)(316+1)
=
(38-1)(38+1)(316+1)
=
(316-1)(316+1)
=
(332-1),
故答案为:
(332-1).
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故答案为:
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