Question

因式分解，求解答

Answer 1

Answer 2

a” - 2ab + b” - 4a + 4b - 12
= ( a - b )” - 4( a - b ) - 12
= ( a - b )” + 2( a - b ) - 6( a - b ) - 12
= ( a - b )( a - b + 2 ) - 6( a - b + 2 )
= ( a - b + 2 )( a - b - 6 )
或者
= ( a - b )" - 6( a - b ) + 2( a - b ) - 12
= ( a - b )( a - b - 6 ) + 2( a - b - 6 )
= ( a - b + 2 )( a - b - 6 )
或者
= ( a - b )" - 4( a - b ) + 4 - 4 - 12
= [ ( a - b ) - 2 ]” - 16
= ( a - b - 2 )" - 4”
= ( a - b - 2 + 4 )( a - b - 2 - 4 )
= ( a - b + 2 )( a - b - 6 )

Answer 3

a²-2ab+b²-4a+4b-12
=(a-b)²-4(a-b)-12
=[(a-b)-6][(a-b)+2]
=(a-b-6)(a-b+2)

Answer 4

a^2-2ab+b^2-4a+4b-12
=(a-b)^2-4(a-b)-12
=(a-b-6)(a-b+2)