Question

求大神帮忙解答(别见笑)

设f(x y)满足f(x x^2)=1 f'y(x y)=x^2+2y,求f(x,y)

Answer 1

f(x,y)=x^2+y^2+2y
=x^2+(y+1)^2-1
≥-1
=f(0,-1)
望采纳~~~