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这道题哪位数学大神会啊啊啊 求解!!!!急!!必有重谢!
1个回答
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f'(θ)=-sinθ+ cosθ/(4√3sin^2θ)
f'(π/6)=-sinπ/6+ cosπ/6/(4√3sin^2π/6)
=-1/2+√3/2/4√3*1/4=-1/2+1/2=0
f'(π/6)=-sinπ/6+ cosπ/6/(4√3sin^2π/6)
=-1/2+√3/2/4√3*1/4=-1/2+1/2=0
追答
谢谢网友采纳
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