Question

存储过程怎么传入数组参数

Answer 1

方法一 分割

例:通过SQL Server存储过程传送数组参数删除多条记录

eg. ID 值为'1,2,3' 以下存储过程就是删除表中id号为1,2,3的记录：

CREATE PROCEDURE DeleteNews
@ID nvarchar(500)
as
DECLARE @PointerPrev int
DECLARE @PointerCurr int
DECLARE @TId int
Set @PointerPrev=1

while (@PointerPrev < LEN(@ID))
Begin
Set @PointerCurr=CharIndex(',',@ID,@PointerPrev)
if(@PointerCurr>0)
Begin
set @TId=cast(SUBSTRING(@ID,@PointerPrev,@PointerCurr-@PointerPrev) as int)
Delete from News where ID=@TID
SET @PointerPrev = @PointerCurr+1
End
else
Break
End
--删除最后一个,因为最后一个后面没有逗号,所以在循环中跳出,需另外再删除
set @TId=cast(SUBSTRING(@ID,@PointerPrev,LEN(@ID)-@PointerPrev+1) as int)
Delete from News where ID=@TID
GO

这个方法麻烦不？于是又有另外一种方法前悔—拦液—临时表

方法二 Table对象

传3个参数，都是数组形式还有时间慧衡正类型用存储过程更新

@Oid = 1,2,3,4

@Did = 111,222,333,444

@DateArr = '2007-1-1,2007-1-2,2007-1-3,2007-1-4'

CREATE proc Test999

@Oid nvarchar(1000) --ID1

,@Did nvarchar(1000) --ID2

,@DateArr nvarchar(1000) --日期

AS

DECLARE @id1s varchar(8000), @id2s varchar(8000), @dates varchar(8000)

set @id1s=@Oid

set @id2s=@Did

set @dates = @DateArr

-- 调用函数实现处理

SELECT @id1s=@id1s, @id2s=@id2s,@dates = @dates

UPDATE A SET terminate_time = B.dt

FROM [Table] A,(

SELECT

id1 = CONVERT(int, Desk_id.value),

id2 = CONVERT(int, room_id.value),

dt = CONVERT(datetime, terminate_time.value)

FROM dbo.f_splitstr(@id1s) Desk_id, dbo.f_splitstr(@id2s) room_id, dbo.f_splitstr(@dates) terminate_time

WHERE Desk_id.id = room_id.id

AND Desk_id.id = terminate_time.id

) B

WHERE A.Desk_id = B.ID1 AND A.room_id = B.ID2

GO这个还用到一个函数f_splitstr

CREATE FUNCTION dbo.f_splitstr(

@str varchar(8000)

)RETURNS @r TABLE(id int IDENTITY(1, 1), value varchar(5000))

AS

BEGIN

DECLARE @pos int

SET @pos = CHARINDEX(',', @str)

WHILE @pos > 0

BEGIN

INSERT @r(value) VALUES(LEFT(@str, @pos - 1))

SELECT

@str = STUFF(@str, 1, @pos, ''),

@pos = CHARINDEX(',', @str)

END

IF @str > ''

INSERT @r(value) VALUES(@str)

RETURN

END