Question

JS通过AJAX到PHP，我想php输出两组HTML返回，并分别显示在Div1和Div2，怎么实现？

JS：
function lieBiaoKuaiClick(gdid){
xmlHttp=new XMLHttpRequest();
xmlHttp.open("POST", '../zwxiaomi/php/zw/huodegongdanxiangxi.php',false);
xmlHttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlHttp.onreadystatechange = function(){
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete"){
document.getElementById("div1").innerHTML=xmlHttp.responseText;
document.getElementById("div2").innerHTML=xmlHttp.responseText;
}
}
xmlHttp.send('tGdId=' + gdid);
}
php：
<?php
$tGdId = $_POST['tGdId'];
include("../gonggong/conn.php");
$query = "select * from zaitugongdan where id = '$tGdId'";
$result = mysqli_query($link, $query);
if (mysqli_num_rows($result) > 0){
$row = mysqli_fetch_array($result);
echo "<table class=\"xianXingBiao\">";
for($i=1; $i<=count($csvzd); $i++) {
echo "<tr><td>".$row[$i]."</td></tr>";
}
echo "</table>";

}else{
echo "<span class=\"spanHongTiShi\">无符号条件的数据</span>";
}

echo "<span>这是要输出到div2的内容</span>";
?>

Answer 1

var p1 ;var num1; function sheetsprice(){ if(document.getElementById("sheets").checked){ num1 = document.getElementById("Numberofsheets").value; p1 = 20*num1; console.log(p1); }else{ alert('请勾选'); } }要么在外部定义全局变量，要么在function内变量前加var
另外如果想提交到php，可以用ajax提交