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微积分,求这道题
1个回答
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y=∫x³√(1+x²)dx=1/2∫x²√(x²+1)dx²
=1/2∫(x²+1)^(3/2)-(x²+1)^(1/2)d(x²+1)
=(1/5)(x²+1)^(5/2)-(1/3)(x²+1)^(3/2)+C
过点(0.1),C=17/15
=1/2∫(x²+1)^(3/2)-(x²+1)^(1/2)d(x²+1)
=(1/5)(x²+1)^(5/2)-(1/3)(x²+1)^(3/2)+C
过点(0.1),C=17/15
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