
c语言 高手请进,帮忙实现一个循环
下面的程序只能打开到C:\01\01.txt,C:\01\02.txt,请帮忙修改循环使其到能够打开到C:\01\07.txt。另外,请帮忙增加一个循环,使打开的文件能从...
下面的程序只能打开到C:\01\01.txt,C:\01\02.txt,
请帮忙修改循环使其到能够打开到C:\01\07.txt。
另外,请帮忙增加一个循环,使打开的文件能从C:\01\01.txt,C:\01\02.txt……直到C:\07\07.txt
# include <stdio.h>
void main()
{
int i;
char*pf[7],*ps[7];
pf[0]="C:\\01\\";
pf[1]="C:\\02\\";
pf[2]="C:\\03\\";
pf[3]="C:\\04\\";
pf[4]="C:\\05\\";
pf[5]="C:\\06\\";
pf[6]="C:\\07\\";
ps[0]="01.txt";
ps[1]="02.txt";
ps[2]="03.txt";
ps[3]="04.txt";
ps[4]="05.txt";
ps[5]="06.txt";
ps[6]="07.txt";
{
FILE *fp[7];
for(i=0;i<7;i++)
{
if((fp[i]=fopen(strcat(pf[0],ps[i]),"r"))== NULL)
{
printf("cannot open i=%d",i);
exit(0);
}
printf("open i=%d\n",i);
pf[0]="C:\\01\\";
}
}
}
tanyuguo ,你的回答我已经调试过了,谢谢!
能帮忙再加一个循环使打开的文件能从C:\01\01.txt,C:\01\02.txt……直到C:\07\07.txt 吗? 展开
请帮忙修改循环使其到能够打开到C:\01\07.txt。
另外,请帮忙增加一个循环,使打开的文件能从C:\01\01.txt,C:\01\02.txt……直到C:\07\07.txt
# include <stdio.h>
void main()
{
int i;
char*pf[7],*ps[7];
pf[0]="C:\\01\\";
pf[1]="C:\\02\\";
pf[2]="C:\\03\\";
pf[3]="C:\\04\\";
pf[4]="C:\\05\\";
pf[5]="C:\\06\\";
pf[6]="C:\\07\\";
ps[0]="01.txt";
ps[1]="02.txt";
ps[2]="03.txt";
ps[3]="04.txt";
ps[4]="05.txt";
ps[5]="06.txt";
ps[6]="07.txt";
{
FILE *fp[7];
for(i=0;i<7;i++)
{
if((fp[i]=fopen(strcat(pf[0],ps[i]),"r"))== NULL)
{
printf("cannot open i=%d",i);
exit(0);
}
printf("open i=%d\n",i);
pf[0]="C:\\01\\";
}
}
}
tanyuguo ,你的回答我已经调试过了,谢谢!
能帮忙再加一个循环使打开的文件能从C:\01\01.txt,C:\01\02.txt……直到C:\07\07.txt 吗? 展开
2个回答
展开全部
首先,pf不能只用char *指针,这样的话,指向的是静态字符串,不能进行strcat操作,要改成
char pf[7][255]={"C:\\01\\","C:\\02\\","C:\\03\\","C:\\04\\","C:\\05\\","C:\\06\\","C:\\07\\;
这样的形式
其次,字符串赋值不能用=,要用strcpy.
改过的程序如下:
#include <stdio.h>
#include "string.h"
#include "stdlib.h"
void main()
{
int i;
char pf[7][255]={"C:\\01\\","C:\\02\\","C:\\03\\","C:\\04\\","C:\\05\\","C:\\06\\","C:\\07\\"},*ps[7];
ps[0]="01.txt";
ps[1]="02.txt";
ps[2]="03.txt";
ps[3]="04.txt";
ps[4]="05.txt";
ps[5]="06.txt";
ps[6]="07.txt";
FILE *fp[7];
for(i=0;i<7;i++)
{
if((fp[i]=fopen(strcat(pf[0],ps[i]),"r"))== NULL)
{
printf("cannot open i=%d",i);
exit(0);
}
printf("open i=%d\n",i);
strcpy(pf[0],"C:\\01\\");
}
}
char pf[7][255]={"C:\\01\\","C:\\02\\","C:\\03\\","C:\\04\\","C:\\05\\","C:\\06\\","C:\\07\\;
这样的形式
其次,字符串赋值不能用=,要用strcpy.
改过的程序如下:
#include <stdio.h>
#include "string.h"
#include "stdlib.h"
void main()
{
int i;
char pf[7][255]={"C:\\01\\","C:\\02\\","C:\\03\\","C:\\04\\","C:\\05\\","C:\\06\\","C:\\07\\"},*ps[7];
ps[0]="01.txt";
ps[1]="02.txt";
ps[2]="03.txt";
ps[3]="04.txt";
ps[4]="05.txt";
ps[5]="06.txt";
ps[6]="07.txt";
FILE *fp[7];
for(i=0;i<7;i++)
{
if((fp[i]=fopen(strcat(pf[0],ps[i]),"r"))== NULL)
{
printf("cannot open i=%d",i);
exit(0);
}
printf("open i=%d\n",i);
strcpy(pf[0],"C:\\01\\");
}
}
展开全部
//如下简洁一些
#include <stdio.h>
#include <stdlib.h>
void main()
{
int i,j;
char pf[30] ;
FILE *fp = NULL;
for(i = 1; i <= 7; i++)
{
for(j = 1; j <= 7; j++)
{
sprintf(pf, "C:\\%2d\\%2d.txt", i, j);
if((fp = fopen(pf, "r")) == NULL)
{
printf("cannot open file %s\n", pf);
exit(0);
}
else
{
printf("open file %s\n",pf);
//do something here
fclose(fp);
}
}
}
}
#include <stdio.h>
#include <stdlib.h>
void main()
{
int i,j;
char pf[30] ;
FILE *fp = NULL;
for(i = 1; i <= 7; i++)
{
for(j = 1; j <= 7; j++)
{
sprintf(pf, "C:\\%2d\\%2d.txt", i, j);
if((fp = fopen(pf, "r")) == NULL)
{
printf("cannot open file %s\n", pf);
exit(0);
}
else
{
printf("open file %s\n",pf);
//do something here
fclose(fp);
}
}
}
}
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询