括号9/23 9/26 9/29,括号除以括号3/23 3/26 3/29,括号等于多少？
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(9/23+9/26+9/29)÷(3/23+3/26+3/29)
=[9×(1/23+1/26+1/29)]÷[3×(1/23+1/26+1/29)]
=9×(1/23+1/26+1/29)÷3÷(1/23+1/26+1/29)
=(9÷3)×[(1/23+1/26+1/29)÷(1/23+1/26+1/29)]
=9÷3×1
=9÷3
=3
=[9×(1/23+1/26+1/29)]÷[3×(1/23+1/26+1/29)]
=9×(1/23+1/26+1/29)÷3÷(1/23+1/26+1/29)
=(9÷3)×[(1/23+1/26+1/29)÷(1/23+1/26+1/29)]
=9÷3×1
=9÷3
=3
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