Question

1.已知 y=sin^2 xln√x-1求dy/dx？

Answer 1

y = sin^2 x * ln√(x-1)
dy/dx = 2 sinx cosx * ln√(x-1) + sin^2 x * 1/√(x-1) * 1/2 * 1/√(x-1)
= sin(2x) * ln√(x-1) + sin^2 x / [2(x-1)]