Question

求一元二次方程解的算法！！！急

求一元二次方程ax平方+bx+c=0的算法过程
会软件编程的请把这道题过程发来

万分感谢！！！！！

Answer 1

看一下这吧，第二张幻灯片http://www.ohzz.com/sourcefile/0/0/1/1642.ppt#264,2,幻灯片 2

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
float a = 1,b = 0, c= 0;
cout<<"a:";
cin>>a;
cout<<"b:";
cin>>b;
cout<<"c:";
cin>>c;
if(a==0)
return 0;
float x1,x2 = 0;
float i;
i = b*b-4*a*c;
if(i<0)
{
cout<<"方程无实根!"<<endl;
return 0;
}
if(i==0)
{
x1 = x2 = (-b)/(2*a);
cout<<"方程有两个相等实数根:"<<endl;
}
if(i>0)
{
x1 = (-b+sqrt(i))/(2*a);
x2 = (-b-sqrt(i))/(2*a);
cout<<"方程有两个不相等实数根:"<<endl;
}
cout <<"X1 = "<<x1<<"\tX2 = "<<x2<<endl;
return 0;
}

Answer 2

用一元二次方程的万能公式！