Question

Ajax,提交带上传数据的表单，服务器端接收不到啊，

$.ajax({
type:"POST",
url:"upload.php",
data:$("sumi").serializeArray(),// 表单元素，和序列化
error:function(){

},
success:function(msg){
alert(msg);
}
});

服务器端，接收不到 $_FILELS的数据啊，求大神，求代码各种求

只用Ajax上传，

Answer 1

sumi 这个元素的代码贴来看下 。是form 中的name么。你可以alert($('sumi'))看下定位元素正确没 。我估计没正确  而且你的data 传递到后台的有错吧。我一般是这样写的

   $.ajax({
                dataType: "json",
                data: "post",
                url: "/MyMember/RTaddLanguage",
                data: {
                    resumeid: resumeid,
                    Language: Language,
                    Degree: Degree
                },
                success: function (result) {
                    if (result.success) {
                        document.getElementById("Language").value = "";
                        document.getElementById("Degree").value = "";
                        document.getElementById("LanguageIdHidden").value = "";
                        var pagerLanguage0 = "";
                        for (var i = 0; r < result.list.length; i++) {
                            pagerLanguage0 += "<div class='jsborder'><div class='ziliaobox'><div class='textziliao'>";
                            pagerLanguage0 += "<div class='textziliaoNext'>语言：</div><div class='textziliaoNextTwo'>" + result.list[i].Language + "</div>";
                            pagerLanguage0 += "<div style='clear: both;'></div></div><div class='textziliao'>";
                            pagerLanguage0 += "<div class='textziliaoNext'>程度：</div><div class='textziliaoNextTwo'>" + result.list[i].Degree + "</div>";
                            pagerLanguage0 += "<div style='clear: both;'></div></div><div style='clear: both;'></div></div><div class='Delete' style='display: block;'>";
                            pagerLanguage0 += "<div style='clear: both;'></div></div><div style='clear: both;'></div></div><div class='Delete' style='display: block;'>";
                        }

                    }
                    else { }
                },
                error: function () {
                    alert("服务器错误!");
                }

追问

追答

$("#sumi").serializeArray()

追问

data:$("sumi").serializeArray(),// 表单元素，和序列化 我上面就是这样写接收不到，才问的啊

追答

$("#sumi").serializeArray(),注意 #