Question

求问一道C语言的题！reverse the sentence，求给出代码

Input an English sentence, reverse the order of words in the sentence, but the order of characters in every word remains. Every word in a sentence is separated by spaces, treat punctuation as common alphabet.
Examples of the input/output of the program are as follows.
Input and Output:
I am a student.
student. a am I

Answer 1

#include <stdio.h>
#include <string.h>
int main()
{
	char instr[100], outstr[100], stack[100];
	int i, n, k, j;
	printf ("Input a string : ");
	gets(instr);
	n = strlen(instr);
	for (i = n-1, j = 0; i >= 0; i--) {
		k = 0;
		while (instr[i] != ' ' && i >= 0) {
			stack[k++] = instr[i--];
		}
		k -= 1;
		while (k >= 0) {
			outstr[j++] = stack[k--];
		}
		outstr[j++] = ' ';
	}
	outstr[j] = '\0';
	printf ("%s\n", outstr);
	return 0;
}

 

Answer 2

这题目 ... 又是送分题了 ...
用 strtok 分割句子，用 string 数组保留 word，
然后逆向输出 word ...

#include <stdio.h>

char * sentence = "I am a student";
char word_list[ 125 ][ 50 ] = { 0 };
int word_count = 0;

while( true )
{
char * token = strtok( sentence, " " );
if( ! token ) break;
strcpy( word_list[ word_count ], token );
word_count ++;
}

while( word_count )
{
printf( "%s\n", word_list[ word_count ] );
word_count --;
}

Answer 3

#include<stdio.h>
#include<string.h>
void main()
{
int i,j,l=0,a=0,k=0;
char s[50],c[50];
gets(s);
for(i=0;s[i]!='\0';i++);
i--;
for(j=i;j>=0;j--)
{
if(s[j]!=' ')
l++;
else
{
k=1;
while(l)
{
c[a]=s[j+k];
a++;
k++;
l--;
}
c[a]=' ';
a++;

}
}
k=1;
while(l)
{
c[a]=s[j+k];
a++;
l--;k++;
}
c[a]='\0';
puts(c);
}