Question

java 用多线程模拟龟兔赛跑：

乌龟和兔子进行1000米赛跑，兔子前进5米，乌龟只能前进1米。但兔子每20米要休息500毫秒，而乌龟是每100米休息500毫秒。谁先到终点就结束程序，并显示获胜方

Answer 1

public class TortoiseAndHareRace {
public static void main(String[] args) {
Runnable vs=new Race();
Thread hare=new Thread(vs,"Hare");
Thread tortoise =new Thread(vs,"Tortoise");
System.out.println("Ready!GO!");
hare.start();
tortoise.start();
}
}
class Race implements Runnable{
private static final int S=1000;
@Override
public void run() {
if(Thread.currentThread().getName().equals("Hare")){
int sHare=0;
while(sHare<=S){
sHare+=5;
if(sHare%20==0)
try {Thread.sleep(500);} catch (InterruptedException e) {e.printStackTrace();}
}
}else{
int sTortoise=0;
while(sTortoise<=S){
sTortoise++;
if(sTortoise%100==0)
try {
Thread.sleep(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}