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(x+y)(x-y)-(4x³y-8xy³)÷2xy
=x²-y²-2x²+4y²
=3y²-x²
=3(√3/3)²-(-1)²
=3×1/3+1
=1+1
=2
x²-4x-1=0
x²-4x+4-5=0
(x-2)²-5=0
(x-2)²=5
(2x-3)²-(x+y)(x-y)-y²
=4x²-12x+9-x²+y²-y²
=3x²-12x+9
=3×(x²-4x+3)
=3×(x²-4x+4-1)
=3×[(x-2)²-1]
=3×(5-1)
=3×4
=12
=x²-y²-2x²+4y²
=3y²-x²
=3(√3/3)²-(-1)²
=3×1/3+1
=1+1
=2
x²-4x-1=0
x²-4x+4-5=0
(x-2)²-5=0
(x-2)²=5
(2x-3)²-(x+y)(x-y)-y²
=4x²-12x+9-x²+y²-y²
=3x²-12x+9
=3×(x²-4x+3)
=3×(x²-4x+4-1)
=3×[(x-2)²-1]
=3×(5-1)
=3×4
=12
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