Question

“Student::Student(int,char,char)”: 不能将参数 2 从“const char [8]”转换为“char” 1>

#include <iostream>

using namespace std;

class Student
{
public:
Student(int n,char nam,char s)
{
num=n;
name=nam;
sex=s;
cout<<"constructor called."<<endl;
}
~Student()
{
cout<<"destructor called."<<endl;
}
void display()
{
cout<<"num:"<<num<<endl;
cout<<"name:"<<name<<endl;
cout<<"sex:"<<sex<<endl;
}

private:
int num;
char name;
char sex;
};
int main()
{
Student stud1(10,"wang_li",'f');
stud1.display();
Student stud2(11,"zang_li",'c');
stud2.display();
return(0);
}

Answer 1

不得不陪你是个才人，首先是名字；你 定义一个字符，那只能放子一个字母；要不就定义成字符串，要不就定义成字符指针；其次就是在写函数的参数时，要不就定义成引用，要不就定义成指针；如果不求返回，你可以直接定义成你的模样；

追问

怎么改，谢谢

追答

#include

using namespace std;

class Student
{
public:
Student(int &n,char *nam,char* s)
{
this->num=n;
this->name=nam;
this->sex=s;
cout<<"constructor called."<<endl;
}
~Student()
{
cout<<"destructor called."<<endl;
}
void display()
{
cout<<"num:"<<num<<endl;
cout<<"name:"<<*name<<endl;
cout<<"sex:"<<*sex<<endl;
}

private:
int num;
char *name;
char *sex;
};
int main()
{
Student stud1(10,"wang_li",'f');
stud1.display();
Student stud2(11,"zang_li",'c');
stud2.display();
return(0);
}