求解第2题
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y'=[f²(x²)]'
=2f(x²)·[f(x²)]'
=2f(x²)·f'(x²)·(x²)'
=2f(x²)·f'(x²)·2x
=4x·f(x²)·f'(x²)
=2f(x²)·[f(x²)]'
=2f(x²)·f'(x²)·(x²)'
=2f(x²)·f'(x²)·2x
=4x·f(x²)·f'(x²)
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