
如何获取url中的参数
1个回答
展开全部
//获取请求url中参数的值:
/*方法一:参数值中没有等于号(“=”)*/
function getUrlRequest() {
var url = location.search; //获取url中"?"符后的字串
var theRequest = new Object();
if (url.indexOf("?") != -1) {
var str = url.substr(1);
if (str.indexOf("&") != -1) {
strs = str.split("&");
for (var i = 0; i < strs.length; i++) {
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
}
} else {
theRequest[str.split("=")[0]] = unescape(str.split("=")[1]);
}
}
return theRequest;
}
/*方法二:参数值中有等于号的情况(“=”)*/
function getUrlRequest(){
var url = location.search; //获取url中"?"符后的字串
var theRequest = new Object();
if (url.indexOf("?") != -1) {
var str = url.substr(1);
if (str.indexOf("&") != -1) {
strs = str.split("&");
for (var i = 0; i < strs.length; i++) {
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
}
} else {
var key = str.substring(0,str.indexOf("="));
var value = str.substr(str.indexOf("=")+1);
theRequest[key] = decodeURI(value);
}
}
return theRequest;
}
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询
广告 您可能关注的内容 |