Question

jquery easyui datagrid 通过spring2.5.6 mvc 来传输数据，页面url改如何写，Controller里面如何写？

Answer 1

我也用springMVC写的代码，一般Controller里面这么写的：
@RequestMapping(value = "/mng/getappinfo", method = RequestMethod.POST)
@ResponseBody //别人跟我说加了这行返回json数据，不加只有上面那行会返回一个页面
public griddata getAppInfo(
@RequestParam(value = "user", required = false) String user,
@RequestParam(value = "roleid", required = false) String roleid){
griddata gdata = new griddata(appInfoService.getAppInfo(user));//这里从数据库获取字段，是个list
return gdata;
}

// 下面这个是griddata的类
public class griddata {
public griddata() {
super();
}
public griddata(List rows) {
super();
this.rows = rows;
}
private List rows;
public List getRows() {
return rows;
}
public void setRows(List rows) {
this.rows = rows;
}
}

js里面的代码应该都差不多

可以参考一下我这边的写法