三重积分的计算问题,请大神看一下?
题目和答案在下面,但是我怎么也算不对,我觉得式子没列错,我怀疑是计算上的问题,我实在找不出来是哪里错了,请大家帮忙看看,谢谢!...
题目和答案在下面,但是我怎么也算不对,我觉得式子没列错,我怀疑是计算上的问题,我实在找不出来是哪里错了,请大家帮忙看看,谢谢!
展开
2个回答
展开全部
V = 2∫<0, π/2>dt∫<0, acost>√(a^2-r^2)rdr
= -∫<0, π/2>dt∫<0, acost>√(a^2-r^2)d(a^2-r^2)
= -∫<0, π/2>dt [(2/3)(a^2-r^2)^(3/2)]<0, acost>
= (2/3)a^3∫<0, π/2>[1-(sint)^3]dt = (2/3)a^3{π/2-∫<0, π/2>(sint)^3dt}
= (2/3)a^3{π/2+∫<0, π/2>[1-(cost)^2]dcost}
= (2/3)a^3{π/2+[cost-(cost)^3/3]<0, π/2>} = (2/3)a^3(π/2-2/3)
= -∫<0, π/2>dt∫<0, acost>√(a^2-r^2)d(a^2-r^2)
= -∫<0, π/2>dt [(2/3)(a^2-r^2)^(3/2)]<0, acost>
= (2/3)a^3∫<0, π/2>[1-(sint)^3]dt = (2/3)a^3{π/2-∫<0, π/2>(sint)^3dt}
= (2/3)a^3{π/2+∫<0, π/2>[1-(cost)^2]dcost}
= (2/3)a^3{π/2+[cost-(cost)^3/3]<0, π/2>} = (2/3)a^3(π/2-2/3)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询
广告 您可能关注的内容 |