Question

解方程，谢了

（ 1 2 x+1）+[ 1 2 （x- 1 2 x-1）+1]+ 1 2 {（x- 1 2 x-1）-[ 1 2 （x- 1 2 x-1）+1]}+1=x
（ 1/ 2 x+1）+[ 1/ 2 （x- 1 /2 x-1）+1]+ 1 /2 {（x- 1 /2 x-1）-[ 1/ 2 （x- 1 /2 x-1）+1]}+1=x

Answer 1

（ 1 2 x+1）+[ 1 2 （x- 1 2 x-1）+1]+ 1 2 {（x- 1 2 x-1）-[ 1 2 （x- 1 2 x-1）+1]}+1=x
（ 1 2 x+1）+[ 1 2 （- 1 1 x-1）+1]+ 1 2 {（- 1 1 x-1）-[ 1 2 （- 1 1 x-1）+1]}+1=x
（ 1 2 x+1）+[-132x-12+1]+ 1 2 {（- 1 1 x-1）-[ -132x-12+1]}+1=x
（ 1 2 x+1）+[-132x-11]+ 1 2 {（- 1 1 x-1）-[ -132x-11]}+1=x
1 2 x+1-132x-11+ 1 2 {- 1 1 x-1+132x+11}+1=x
-120x-10+1 2 {121x+10}+1=x
-121x-9+1 2 {121x+10}=0
-121x-9+{1452x+120}=0
-121x-9+1452x+120=0
1331x+111=0
1331x=-111
x=-111/1331

Answer 2

102x+1+(12x-144x-12)+12(x-12x-1-(12x-144x-12+1))+1=x
102x+1+12x-144x-12+12（x-12z-1-12x+144x+12-1)+1=x
102x+1+12x-144x-12+12x-144x-12-144x+1728x+144-12=x
1422x+109=x
x=-109/1421