Question

各学霸们，帮帮忙吧！！！

Answer 1

sin10π/3-根号2cos(-19π/4)+tan(13π/3)
=-sinπ/3-√2cos(3π/4)+tan(π/3)
=-√3/2+1+√3
=1-(√3/2)
10、sin(π-a)cos(2π-a)sin(-a+1.5π)/(tan(-a-π)sin(-π-a）)
=sin(a)cos(a)sin(-a-0.5π)/(tan(-a)sin(π-a-2π）)
=(-1)^2*sin(a)cos(a)cos(a)/(tan(a)sin(π-a）)
=sin(a)cos(a)cos(a)/(tan(a)sin(a）)
=cos(a)cos(a)/tan(a)

sina-2cosa=0==>tan(a)=2
sina-2cosa=0==>sin(a)^2=4cos(a)^2==>1=5cos(a)^2==>cos(a)^2=1/5
所以
cos(a)cos(a)/tan(a)=0.1
（希望能帮到你，也希望你能给我好评哦，你的好评是我最大的鼓励！谢谢~）