
1/根号下(8+2x–x2)的不定积分
1个回答
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∫dx/√(8+2x-x^2) = ∫dx/√[9-(x-1)^2]
= (1/3)∫dx/√{1-[(x-1)/3]^2}
= ∫d[(x-1)/3]/√{1-[(x-1)/3]^2}
= arcsin[(x-1)/3]+C
= (1/3)∫dx/√{1-[(x-1)/3]^2}
= ∫d[(x-1)/3]/√{1-[(x-1)/3]^2}
= arcsin[(x-1)/3]+C
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