初二上计算a^3(ab^2+b^3)^2÷(1/2ab)^2÷(a+b)^2？
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a^3(ab^2+b^3)^2÷(1/2ab)^2÷(a+b)^2
=4(a^4b^2+a^3b^3)÷(ab)^2÷(a+b)^2
=4(ab)^2(a^2+ab)÷(ab)^2÷(a+b)^2
=4(a^2+ab)÷(a+b)^2
=4a(a+b)÷(a+b)^2
=4a/(a+b),5,4a/(a+b),1,a^3(ab^2+b^3)^2÷(1/2ab)^2÷(a+b)^2
=a^3(ab^2+b^3)^2/[(1/2ab)^2(a+b)^2]
=a^3*{(ab^2+b^3)/[1/2ab(a+b)]}^2
=a^3*{b^2/[ab/2]}^2
=ab^2/1/4
=4ab^2,0,
=4(a^4b^2+a^3b^3)÷(ab)^2÷(a+b)^2
=4(ab)^2(a^2+ab)÷(ab)^2÷(a+b)^2
=4(a^2+ab)÷(a+b)^2
=4a(a+b)÷(a+b)^2
=4a/(a+b),5,4a/(a+b),1,a^3(ab^2+b^3)^2÷(1/2ab)^2÷(a+b)^2
=a^3(ab^2+b^3)^2/[(1/2ab)^2(a+b)^2]
=a^3*{(ab^2+b^3)/[1/2ab(a+b)]}^2
=a^3*{b^2/[ab/2]}^2
=ab^2/1/4
=4ab^2,0,
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