高中数学,第17题
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y= m(x+1) (1)
y^2=4x (2)
sub (1) into (2)
m^2.(x+1)^2 =4x
m^2.x^2 + (2m^2-4)x + m^2 =0
△=0
(2m^2-4)^2 - 4m^4=0
(m^2-2)^2 -m^4 =0
-4m^2 + 4=0
m^2=1
m=1 or -1
斜率k =1 or -1
y^2=4x (2)
sub (1) into (2)
m^2.(x+1)^2 =4x
m^2.x^2 + (2m^2-4)x + m^2 =0
△=0
(2m^2-4)^2 - 4m^4=0
(m^2-2)^2 -m^4 =0
-4m^2 + 4=0
m^2=1
m=1 or -1
斜率k =1 or -1
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