Question

java数组里面的元素怎么交换

Answer 1

BufferedReader[] buf = new BufferedReader[10]; //申请缓冲数组
int n;
int array[] = new int[10];
for (int i = 0; i < 10; i++) { //赋值
buf[i] = new BufferedReader(new InputStreamReader(System.in)); //给每个缓冲区定义
do { //判断是否是空串，如是则重新输入
n = 1;
System.out.print("请输入第" + (i + 1) + "个整数:");
try { //建立一个异常捕获
array[i] = Integer.parseInt(buf[i].readLine()); //执行串变整数
} catch (NumberFormatException e) { //捕获异常
System.out.println("数据输入错误请重新输入");
n = 0;
} catch (IOException e) {
e.printStackTrace();
}
} while (n == 0);
}
return array;
}

public static void print() {
int[] ary = write();
int s;
System.out.println("\n你输入的数组是:");
for (int i = 0; i < 10; i++) { //输出原数组
System.out.print(ary[i] + " ");
}
for (int i = 0; i < 5; i++) { //对换
s = ary[i];
ary[i] = ary[9 - i];
ary[9 - i] = s;
}
System.out.println("\n对换后的数组是:");
for (int i = 0; i < 10; i++) { //输出对换后数组
System.out.print(ary[i] + " ");
}
System.out.println();
}
}12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849

Answer 2

int[] a = {1,2};
int t = a[0];
a[0] = a[1];
a[1] = t;

Answer 3

int[] a = {1,2};
int a[1]∧ a[0];
a[0] ∧ a[1];
a[1] ∧ a[0];

追答

int[] a = {1,2};
int a[1]∧ a[0];
int[] a = {1,2};
int a[1]∧ a[0];
a[0] ∧ a[1];
a[1] ∧ a[0]≡a[0] ∧ a[1];
int[] a = {1,2};
int a[1]∧ a[0];
a[0] ∧ a[1];
a[1] ∧ a[0]＝[1] ∧ a[0];

Answer 4

肯定是需要的