请问这题计算的规律怎么找?
(1+1/1乘3)乘(1+1/2乘4)乘(1+1/3乘5)乘(1+1/4乘6)乘……乘(1+1/98乘100)=...
(1+1/1乘3)乘(1+1/2乘4)乘(1+1/3乘5)乘(1+1/4乘6)乘……乘(1+1/98乘100)=
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(1+1/n(n+2))
=(1+1/((n+1)^2-1))
=(n+1)^2/(n(n+2))
=n/(n-1) * n/(n+1)
(1+1/1乘3)乘(1+1/2乘4)乘(1+1/3乘5)乘(1+1/4乘6)乘……乘(1+1/98乘100)
=(2/1 * 2/3)*(3/2 * 3/4)*……*(99/98 * 99/100)
=(2/1 * 3/2 * 4/3 *……*99/98) * (2/3 * 3/4 *……*99/100)
=99 * 2/100
=1.98
=(1+1/((n+1)^2-1))
=(n+1)^2/(n(n+2))
=n/(n-1) * n/(n+1)
(1+1/1乘3)乘(1+1/2乘4)乘(1+1/3乘5)乘(1+1/4乘6)乘……乘(1+1/98乘100)
=(2/1 * 2/3)*(3/2 * 3/4)*……*(99/98 * 99/100)
=(2/1 * 3/2 * 4/3 *……*99/98) * (2/3 * 3/4 *……*99/100)
=99 * 2/100
=1.98
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