求解 这道高数题怎么做？
1个回答
展开全部
x=e^t.cost
x(3π/4) = -(√2/2)e^(3π/4)
dx/dt = (cost - sint )e^t
y=e^t.sint
y(3π/4) = (√2/2)e^(3π/4)
dy/dt = ( sint+cost) e^t
dy/dx
=(dy/dt)/(dx/dt)
=( sint+cost) /(cost - sint )
dy/dx| t=3π/4
=0
切线方程; t=3π/4
y- (√2/2)e^(3π/4) =0
x(3π/4) = -(√2/2)e^(3π/4)
dx/dt = (cost - sint )e^t
y=e^t.sint
y(3π/4) = (√2/2)e^(3π/4)
dy/dt = ( sint+cost) e^t
dy/dx
=(dy/dt)/(dx/dt)
=( sint+cost) /(cost - sint )
dy/dx| t=3π/4
=0
切线方程; t=3π/4
y- (√2/2)e^(3π/4) =0
本回答由网友推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
