Question

求积分过程

Answer 1

如图，这是这道题的过程

Answer 2

1-cos2x=2(sinx)^2
∫√[1-cos(2x)]dx=∫√[2(sinx)^2]dx (应用倍角公式)
=√2∫|sinx|dx
=√2[cos(0)-cos(π)]
=√2(1+1)
=2√2.