Question

(a-b/a+b)²×(3a+3b/2a-2b)-(a²-b²/a²)÷(b/a)得多少

Answer 1

你好!
原式=
(a-b)²/(a+b)²
×
3(a+b)
/
[2(a-b)]
-
(a+b)(a-b)
/
a²
×
a/b
=
3(a-b)
/
[2(a+b)]
-
(a+b)(a-b)
/
(ab)
=
3ab(a-b)
/
[2ab(a+b)]
-
2(a+b)²(a-b)
/
[2ab(a+b)]
=
(a-b)[3ab
-
2(a+b)²]
/
[2ab(a+b)]
=
(a-b)[3ab
-
2a²
-
4ab
-
2b²]
/
[2ab(a+b)]
=
-
(a-b)(2a²-ab-2b²)
/
[2ab(a+b)]
只能化简到这一步了，你看看是不是题目抄错了