Question

（4/X）²+（4/20-X）²=17怎么化简？

Answer 1

该分式方程可以这样求解，1、先整理原方程，把方程的分母去掉，转换成一元四次方程；2、用数值分析的方法（如待定系数法）求解方程。

求解过程如下：

Answer 2

（4/X）²+（4/20-X）²=17怎么化简？
两边都乘以x^2(20-x)^2,得
16(20-x)^2+16x^2=17x^2(20-x)^2,
16(400-40x+x^2)+16x^2=17x^2(400-40x+x^2),
整理得17x^4-680x^3+6768x^2+640x-6400=0.

Answer 3

解；16/x^2+（1/5-x）^2=17,16/x^2+1/25-2x/5+x^2=17,400+x^2-10x^3+25x^4=425x^2,400+x^2-10x^3+25x^4-425x^2=0,25x^4-10x^3-424x^2+400=0.

Answer 4

16/x^2+（1/5-x）^2
=17,16/x^2+1/25-2x/5+x^2
=17,400+x^2-10x^3+25x^4
=425x^2,400+x^2-10x^3+25x^4-425x^2
=0,25x^4-10x^3-424x^2+400
=0

Answer 5

两边都乘以x^2(20-x)^2,得
16(20-x)^2+16x^2=17x^2(20-x)^2,
16(400-40x+x^2)+16x^2=17x^2(400-40x+x^2),
整理得17x^4-680x^3+6768x^2+640x-6400=0.
可以吗？