Question

y=x/1+2根号+5微分？

Answer 1

求y=1/x+2根号x的微分
答案：
dy=d(1/x+2√x)=d(1/x)+d(2√x) =-1/x²dx+2×1/2×x^(1/2-1)dx =-1/x²dx+x^(-1/2)dx =[-1/x²+x^(-1/2)]dx