Question

在c语言二维数组中怎样交换两个数组元素中的字符串,请写代码.

c语言二维数组中怎样交换两个数组元素中的字符串,请写代码.

Answer 1

int strcpy(char *s1,const char *s2);
开辟一个缓冲区，比如
char buff[100];//假设你的字符串不超过这么多

而你的而为数组为
char **argv;
其中argv[0] = "this is the first string";
argv[1] = "this is the seconde string";

你只须调用如下
strcpy(buff,argv[0]);
strcpy(argv[0],argv[1]);
strcpy(argv[1],buff);

一下是完整代码，并测试过
#include <stdio.h>
#include <string.h>

char argv[2][100]={ "This is the first string","This is the second string"};
// 存储字符串的二维数组，每个字符串最长为99个字节
char buff[100];
//缓冲区
int main()
{
printf("转换前：\n");
printf("argv[0] = %s\n",argv[0]);
printf("argv[1] = %s\n",argv[1]);

strcpy(buff,argv[0]);
strcpy(argv[0],argv[1]);
strcpy(argv[1],buff);

printf("转换后：\n");
printf("argv[0] = %s\n",argv[0]);
printf("argv[1] = %s\n",argv[1]);

return 0;
}

Answer 2

char c[20];
strcpy(c, b);
strcpy(b, a);
strcpy(a, c);