Question

求出式子 I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+。。。+I1/100-1/99I （I I 表示绝对值）

Answer 1

因为1/3-1/2是负数，外面加了绝对值符号，所以 I1/3-1/2I= -（1/3-1/2）
把整个式子的绝对值拆开
= -（1/3-1/2）-（1/4-1/3）-(1/5-1/4)...-(1/100-1/99)
=-1/3+1/2-1/4+1/3-1/5+1/4...-1/100+1/99
=1/2-1/100
=50/100-1/100
=49/100

Answer 2

I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+。。。+I1/100-1/99I
=1/2-1/3+1/3-1/4+...+1/99-1/100
=1/2-1/100
=49/100

Answer 3

I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+。。。+I1/100-1/99I
=(1/2-1/3)+(1/3-1/4)....+(1/99-1/100)
去绝对值fuhao
=1/2-1/3+1/3-1/4。。。。+1/99-1/100
=1/2-1/100
=49/100