Question

怎么化简代数式

如〈4x-2y〕-〖-〔-2y-x〕+〔x-y〕〗-5x
〖〗是中括号
怎么化简
2x^2y+2xy-[3x^2y-2(-3xy^2+2xy)]-4xy^2
^2是平方

Answer 1

〈4x-2y〕-〖-〔-2y-x〕+〔x-y〕〗-5x
=〈4x-2y〕-〖2y+x+x-y〗-5x
=〈4x-2y〕- (y+2x)-5x
=〈4x-2y〕- y-7x
=-3x-3y
=-3(x+y)

Answer 2

4X-2Y-[2Y+X+X-Y]-5X
=4X-2Y-2Y-X-X+Y-5X
=4X-X-X-5X-2Y-2Y+Y
=-3X-3Y
2x^2y+2xy-[3x^2y-2(-3xy^2+2xy)]-4xy^2
=2x^2y+2xy-[3x^2y+6xy^2-4xy]-4xy^2
=2x^2y+2xy-3x^2y-6xy^2+4xy-4xy^2
=-x^2y-10xy^2+6xy

Answer 3

4x-2y+(-2y-x)-(x-y)-5x
4x-2y-2y-x-x+y-5x
-3x-3y
-3(x+y)

Answer 4

(4x-2y)-[-(-2y-x)+(x-y)]-5x
=(4x-2y)-[2y+x+x-y]-5x
=(4x-2y)-[y+2x]-5x
=4x-2y-y-2x-5x
=-3x-3y
=-3(x-y)

Answer 5

合并同类项，同底数幂相乘，底数不变，指数想加。