解方程哦
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（x-1+1)/(x-1)-(x-2+1)/(x-2)=(x-4+1)/(x-4)-(x-5+1)/(x-5)
1+1/(x-1)-[1+1/(x-2)]=1+1/(x-4)-[1+1/(x-5)]
1/(x-1)-1/(x-2)=1/(x-4)-1/(x-5)
[(x-2)-(x-1)]/[(x-1)(x-2)]=[(x-5)-(x-4)]/[(x-4)(x-5)]
-1/[(x-1)(x-2)]=-1/[(x-4)(x-5)]
1/[(x-1)(x-2)]=1/[(x-4)(x-5)]
(x-4)(x-5)=(x-1)(x-2)
x²-9x+20=x²-3x+2
-6x=-18
x=3
经检验x=3是原方程的解
1+1/(x-1)-[1+1/(x-2)]=1+1/(x-4)-[1+1/(x-5)]
1/(x-1)-1/(x-2)=1/(x-4)-1/(x-5)
[(x-2)-(x-1)]/[(x-1)(x-2)]=[(x-5)-(x-4)]/[(x-4)(x-5)]
-1/[(x-1)(x-2)]=-1/[(x-4)(x-5)]
1/[(x-1)(x-2)]=1/[(x-4)(x-5)]
(x-4)(x-5)=(x-1)(x-2)
x²-9x+20=x²-3x+2
-6x=-18
x=3
经检验x=3是原方程的解
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