请给出详细的解题过程，一定采纳！谢谢。
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sin(-7π/3)cos(7π/6)-sin(11π/6)cos(-5π/3)
=sin(-2π-π/3)cos(π+π/6)-sin(2π-π/6)cos(-2π+π/3)
=sin(-π/3)[-cos(π/6)]-sin(-π/6)cos(π/3)
=sin(π/3)cos(π/6)+sin(π/6)cos(π/3)
=sin(π/3+π/6)
=sin(π/2)
=1
=sin(-2π-π/3)cos(π+π/6)-sin(2π-π/6)cos(-2π+π/3)
=sin(-π/3)[-cos(π/6)]-sin(-π/6)cos(π/3)
=sin(π/3)cos(π/6)+sin(π/6)cos(π/3)
=sin(π/3+π/6)
=sin(π/2)
=1
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sin(-7π/3). cos(7π/3) - sin(11π/6).cos(-5π/3)
=-sin(7π/3). cos(7π/3) - sin(11π/6).cos(5π/3)
=-(1/2)sin(14π/3) - (-sin(π/6)).cos(π/3)
=-(1/2)sin(2π/3) + sin(π/6).cos(π/3)
=-(1/2)(√3/2) + (1/2)(1/2)
=-√3 +1
=-sin(7π/3). cos(7π/3) - sin(11π/6).cos(5π/3)
=-(1/2)sin(14π/3) - (-sin(π/6)).cos(π/3)
=-(1/2)sin(2π/3) + sin(π/6).cos(π/3)
=-(1/2)(√3/2) + (1/2)(1/2)
=-√3 +1
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