数据结构c语言复数运算
#include<stdio.h>#include<stdlib.h>typedefstruct{doubler,i;//r为实部,i为虚部}complex;comple...
#include <stdio.h>#include<stdlib.h>typedef struct{ double r,i; //r为实部,i为虚部 }complex; complex* add(complex *a,complex *b); //复数a + 复数b complex* minus(complex *a,complex *b); //复数a - 复数b complex* multiply(complex *a,complex *b); //复数a * 复数b void printComplex(complex *a); //输出 complex* add(complex *a,complex *b) { complex *add; int m,n; m = a->r; n = b->r; add->r = m+n; m = a->i; n = b->i; add->i = m+n; return add;}complex* minus(complex *a,complex *b) { complex *minus; int o,p; o = a->r; p = b->r; minus->r = o-p ; o =a->i; p = b->i; minus->i = o-p; return minus;}complex* multiply(complex *a,complex *b) { complex *multiply; int u,w,s,t; u = a->r; w = b->r; s = a->i; t = b->i; multiply->r = u*w-s*t; multiply->i = s*w+u*t; return multiply;}void printComplex(complex *a) { if(a->i==0) printf("%.2lf + 0.00i\n",a->r); else if(a->r==0) printf("0.00 + %.2lfi\n",a->i); else printf("%.2lf + %.2lfi\n",a->r,a->i);}int main(){ complex a,b,*re; char c; while(~scanf("%lf %lf %lf %lf %c",&a.r,&a.i,&b.r,&b.i,&c)){ switch(c){ case '+': re = add(&a,&b); break; case '-': re = minus(&a,&b); break; case '*': re = multiply(&a,&b); break; default:; } printComplex(re); free(re); } return 0;}有大佬能帮我改一下吗?主函数和开头的结构体是已知的,那些接口实现是自己写的,但是总是RunError,只用改那些接口函数
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/*
c语言复数运算
*/
#include<stdio.h>
#include<stdlib.h>
typedef struct
{
double r,i; //r为实部,i为虚部
}complex;
complex* add(complex *a,complex *b); //复数a + 复数b
complex* minus(complex *a,complex *b); //复数a - 复数b
complex* multiply(complex *a,complex *b); //复数a * 复数b
void printComplex(complex *a); //输出
complex* add(complex *a,complex *b) {
complex *add;
add->r =a->r+b->r;
add->i =a->i+b->i;
return add;
}
complex* minus(complex *a,complex *b)
{
complex *minus;
minus->r =a->r-b->r;
minus->i =a->i-b->i;
return minus;
}
complex* multiply(complex *a,complex *b)
{
complex *multiply;
multiply->r = a->r*b->r-a->i*b->i;
multiply->i = a->i*b->r+a->r*b->i;
return multiply;
}
void printComplex(complex *a) //输出要注意虚部有负数的情况
{
if(a->r!=0)
printf("%.2lf",a->r); //不要断行,先输出实部
else
printf("0.00");
if(a->i>0) //大于0,正常输出+虚部
printf(" + %.2lfi\n",a->i);
else if(a->i<0) //虚部是负数,不用输出+号了,直接输出负数
printf(" %.2lfi\n",a->i);
else
printf(" + 0.00i\n");//虚部为0
}
帮你改了下,再去试试吧。一时之间我也想不出还有什么漏洞了。祝好运。如果是自己写主函数的话,改一改那个输入吧,输入很容易会造成问题的
这一句: scanf("...%f %c ",...,c),一个不好输入就会出错,c可能会获取到空白。
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