(1)若x+1/x=3,求x^2/(x^4+x^2+1)的值. (2)若1/x-1/y=2,求(4
(1)若x+1/x=3,求x^2/(x^4+x^2+1)的值.(2)若1/x-1/y=2,求(4x+5xy-4y)/(x-3xy-y)的值....
(1)若x+1/x=3,求x^2/(x^4+x^2+1)的值.
(2)若1/x-1/y=2,求(4x+5xy-4y)/(x-3xy-y)的值. 展开
(2)若1/x-1/y=2,求(4x+5xy-4y)/(x-3xy-y)的值. 展开
3个回答
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(1)
x+1/x=3
x^2+1/x^2 +2 =9
x^2+1/x^2 =7
x^2/(x^4+x^2+1)
=1/( x^2 +1 +1/x^2)
=1/(7+1)
=1/8
(2)
1/x-1/y=2
y-x =2xy
x-y =-2xy
(4x+5xy-4y)/(x-3xy-y)
=[ 4(x-y)+5xy] /[ (x-y) -3xy]
=(-8+5).( -2 -3)
=3/5
x+1/x=3
x^2+1/x^2 +2 =9
x^2+1/x^2 =7
x^2/(x^4+x^2+1)
=1/( x^2 +1 +1/x^2)
=1/(7+1)
=1/8
(2)
1/x-1/y=2
y-x =2xy
x-y =-2xy
(4x+5xy-4y)/(x-3xy-y)
=[ 4(x-y)+5xy] /[ (x-y) -3xy]
=(-8+5).( -2 -3)
=3/5
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